is a tangent to the circle with centre O to B. AB is a chord of length 24 cm at a distance of 5 cm from the centre. If the tangent is of length 20 cm, find the length of PO.Read more on Sarthaks.com – https://www.sarthaks.com/176103/pb-is-tangent-the-circle-with-centre-is-chord-of-length-24-cm-at-distance-of-cm-from-the-centre

OM=5~cm

MSESHSEOM LAB and M is mid-point of AB,

= 12 cm.

In right-angled triangle A OMB,

OB^{2}=OM^{2}+MB^{2}

+OB^{2}=5^{2}+12^{2}

OB^{2}=25+144

OB^{2}=169

\Rightarrow OB=169~cm OB=13~cm.

As BP is tangent to circle at B, OB 1 BP. In right-angled triangle ▲ OBP,

OP^{2}=OB^{2}+BP^{2}

OP^{2}=13^{2}+20^{2}

*OP=\sqrt{}569~cm

Hence, the length of OP=\sqrt{}569~cm.