Maths
is a tangent to the circle with centre O to B. AB is a chord of length 24 cm at a distance of 5 cm from the centre. If the tangent is of length 20 cm, find the length of PO.Read more on Sarthaks.com – https://www.sarthaks.com/176103/pb-is-tangent-the-circle-with-centre-is-chord-of-length-24-cm-at-distance-of-cm-from-the-centre
OM=5~cm MSESHSEOM LAB and M is mid-point of AB, = 12 cm. In right-angled triangle A OMB, OB^{2}=OM^{2}+MB^{2} +OB^{2}=5^{2}+12^{2} OB^{2}=25+144 OB^{2}=169 \Rightarrow OB=169~cm OB=13~cm. As BP is tangent to circle at B, OB 1 BP. In right-angled triangle ▲ OBP, OP^{2}=OB^{2}+BP^{2} OP^{2}=13^{2}+20^{2} *OP=\sqrt{}569~cm Hence, the length of OP=\sqrt{}569~cm.