Tangents PQ and PR to a circle with center O.
To prove: PQ = PR.
Proof:
OQ is common to both triangles:*
OQ is the radius of the circle, and it is common to both triangles.
- OR is common to both triangles:
OR is the radius of the circle, and it is common to both triangles.
- QOR = ∠PQR (both are right angles):
The common side OQ and OR are shared, and the right angles are equal.
- By the Right-Angle Hypotenuse-Leg Congruence Theorem:
- Triangles QOR and PQR are congruent.
- Therefore, corresponding sides are equal:
